-4.9x^2-9x+500=0

Solution for -4.9x^2-9x+500=0 equation:

-4.9x^2-9x+500=0

a = -4.9; b = -9; c = +500;
Δ = b2-4ac
Δ = -92-4·(-4.9)·500
Δ = 9881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{9881}}{2*-4.9}=\frac{9-\sqrt{9881}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{9881}}{2*-4.9}=\frac{9+\sqrt{9881}}{-9.8}
$